Asked by John

express the given quantity as a single logarithm: ln(a+b)+ln(a-b)-8ln(c)
Answered by drwls
ln[(a+b)(a-b)c^8]
= ln[8c(a^2-b^2)]
Answered by drwls
I overlooked the minus sign.

ln[(a+b)(a-b)/c^8]
= ln[(a^2-b^2)/8c]
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