Question
Use the table of molar masses to complete the question. Do NOT use any other values except the ones provided in the table below. Element Molar Mass (g/mol) carbon 12.01 hydrogen 1.01 oxygen 16.00 A chemist will use a sample of 30g of glucose ( C6H12O6 ) in an experiment. Determine the number of moles of glucose the chemist will use based on the molar mass values provided in the table. (Your value should be rounded to 2 decimal places; i.e. the hundredths place). (2 points) The number of moles the chemist will use is: moles
Answers
GPT-4o mini
To determine the number of moles of glucose (C₆H₁₂O₆) in a 30 g sample, we first need to calculate the molar mass of glucose using the molar masses provided.
**Calculating the molar mass of glucose (C₆H₁₂O₆):**
- Carbon (C): 6 atoms × 12.01 g/mol = 72.06 g/mol
- Hydrogen (H): 12 atoms × 1.01 g/mol = 12.12 g/mol
- Oxygen (O): 6 atoms × 16.00 g/mol = 96.00 g/mol
Now, adding these together:
\[
\text{Molar mass of glucose} = 72.06 \, \text{g/mol} + 12.12 \, \text{g/mol} + 96.00 \, \text{g/mol} = 180.18 \, \text{g/mol}
\]
Next, we can calculate the number of moles of glucose using the formula:
\[
\text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}}
\]
Substituting the values:
\[
\text{Number of moles} = \frac{30 \, \text{g}}{180.18 \, \text{g/mol}} \approx 0.1665
\]
Rounding this to two decimal places:
The number of moles the chemist will use is: **0.17 moles**.
**Calculating the molar mass of glucose (C₆H₁₂O₆):**
- Carbon (C): 6 atoms × 12.01 g/mol = 72.06 g/mol
- Hydrogen (H): 12 atoms × 1.01 g/mol = 12.12 g/mol
- Oxygen (O): 6 atoms × 16.00 g/mol = 96.00 g/mol
Now, adding these together:
\[
\text{Molar mass of glucose} = 72.06 \, \text{g/mol} + 12.12 \, \text{g/mol} + 96.00 \, \text{g/mol} = 180.18 \, \text{g/mol}
\]
Next, we can calculate the number of moles of glucose using the formula:
\[
\text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}}
\]
Substituting the values:
\[
\text{Number of moles} = \frac{30 \, \text{g}}{180.18 \, \text{g/mol}} \approx 0.1665
\]
Rounding this to two decimal places:
The number of moles the chemist will use is: **0.17 moles**.