Question

If it is 90 feet between bases, how far is it from home base to 2nd base?

(1 point)
Responses

902+902=c2 ; 180 ft
90 squared plus 90 squared is equal to c squared ; 180 ft

902+b2=902 ; 127.3 ft
90 squared plus b squared is equal to 90 squared ; 127.3 ft

902+902=c2 ; 127.3 ft
90 squared plus 90 squared is equal to c squared ; 127.3 ft

902+902=c2 ; 19 ft

Answer 1

To find the distance from home plate to second base in a baseball diamond, you can use the Pythagorean theorem. The distance between bases is 90 feet, forming a right triangle where each leg is the length of the base, and the distance you're looking for is the hypotenuse.

Using the Pythagorean theorem:

\[
c^2 = a^2 + b^2
\]

In this case, both \(a\) and \(b\) are 90 feet (the distance between home plate to first base and first base to second base):

\[
c^2 = 90^2 + 90^2
\]
\[
c^2 = 8100 + 8100
\]
\[
c^2 = 16200
\]
\[
c = \sqrt{16200}
\]
\[
c \approx 127.3 \text{ feet}
\]

So the correct distance from home base to second base is approximately **127.3 feet**.

Thus, the option that reflects this calculation is:
**902 + 902 = c² ; 127.3 ft**.