Question
There are 6 of 1/3 inch cubes packed together and are one cube wide, two cubes in height and 3 cubes in length, what’s the volume of the right rectangular prism in that order, enter answer as fraction and do not reduce
Answers
GPT-4o mini
To find the volume of a right rectangular prism, we use the formula:
\[
\text{Volume} = \text{length} \times \text{width} \times \text{height}
\]
Given that each cube has a side length of \( \frac{1}{3} \) inch, we first determine the dimensions of the right rectangular prism based on the arrangement of the cubes:
- Width: 1 cube wide = \( \frac{1}{3} \) inch
- Height: 2 cubes high = \( 2 \times \frac{1}{3} = \frac{2}{3} \) inch
- Length: 3 cubes long = \( 3 \times \frac{1}{3} = 1 \) inch
Now we can calculate the volume:
\[
\text{Volume} = \left( \frac{1}{3} \right) \times \left( \frac{2}{3} \right) \times (1)
\]
Calculating:
\[
\text{Volume} = \frac{1}{3} \times \frac{2}{3} = \frac{2}{9}
\]
So, the volume of the right rectangular prism is:
\[
\frac{2}{9}
\]
\[
\text{Volume} = \text{length} \times \text{width} \times \text{height}
\]
Given that each cube has a side length of \( \frac{1}{3} \) inch, we first determine the dimensions of the right rectangular prism based on the arrangement of the cubes:
- Width: 1 cube wide = \( \frac{1}{3} \) inch
- Height: 2 cubes high = \( 2 \times \frac{1}{3} = \frac{2}{3} \) inch
- Length: 3 cubes long = \( 3 \times \frac{1}{3} = 1 \) inch
Now we can calculate the volume:
\[
\text{Volume} = \left( \frac{1}{3} \right) \times \left( \frac{2}{3} \right) \times (1)
\]
Calculating:
\[
\text{Volume} = \frac{1}{3} \times \frac{2}{3} = \frac{2}{9}
\]
So, the volume of the right rectangular prism is:
\[
\frac{2}{9}
\]