Liliana wants to wrap a present in a box for her grandmother. The box measures 4 in. high, 3 in. wide and 10 in. long. How much wrapping paper will Liliana need to wrap the present?(1 point)

Responses

140 in²
140 in²

80 in²
80 in²

152 in²
152 in²

164 in²

1 answer

To determine how much wrapping paper Liliana will need to wrap the present, we need to calculate the surface area of the box. The surface area \( A \) of a rectangular box can be calculated using the formula:

\[ A = 2lw + 2lh + 2wh \]

where:

  • \( l \) is the length,
  • \( w \) is the width,
  • \( h \) is the height.

Given:

  • Length \( l = 10 \) in,
  • Width \( w = 3 \) in,
  • Height \( h = 4 \) in.

Now we can plug in the values:

  1. Calculate the area of the two length-width (lw) faces: \[ 2lw = 2 \times 10 \times 3 = 60 \text{ in}^2 \]

  2. Calculate the area of the two length-height (lh) faces: \[ 2lh = 2 \times 10 \times 4 = 80 \text{ in}^2 \]

  3. Calculate the area of the two width-height (wh) faces: \[ 2wh = 2 \times 3 \times 4 = 24 \text{ in}^2 \]

Now, add these areas together to get the total surface area:

\[ A = 60 + 80 + 24 = 164 \text{ in}^2 \]

Therefore, Liliana will need 164 in² of wrapping paper to wrap the present.

The correct answer is 164 in².