Question

Liliana wants to wrap a present in a box for her grandmother. The box measures 4 in. high, 3 in. wide and 10 in. long. How much wrapping paper will Liliana need to wrap the present?(1 point)
Responses

140 in²
140 in²

80 in²
80 in²

152 in²
152 in²

164 in²

Answer 1

To determine how much wrapping paper Liliana will need to wrap the present, we need to calculate the surface area of the box. The surface area \( A \) of a rectangular box can be calculated using the formula:

\[
A = 2lw + 2lh + 2wh
\]

where:
- \( l \) is the length,
- \( w \) is the width,
- \( h \) is the height.

Given:
- Length \( l = 10 \) in,
- Width \( w = 3 \) in,
- Height \( h = 4 \) in.

Now we can plug in the values:

1. Calculate the area of the two length-width (lw) faces:
\[
2lw = 2 \times 10 \times 3 = 60 \text{ in}^2
\]

2. Calculate the area of the two length-height (lh) faces:
\[
2lh = 2 \times 10 \times 4 = 80 \text{ in}^2
\]

3. Calculate the area of the two width-height (wh) faces:
\[
2wh = 2 \times 3 \times 4 = 24 \text{ in}^2
\]

Now, add these areas together to get the total surface area:

\[
A = 60 + 80 + 24 = 164 \text{ in}^2
\]

Therefore, Liliana will need **164 in²** of wrapping paper to wrap the present.

The correct answer is **164 in²**.