Asked by Kelsey

Cd/Cd2+//H+/H2/Pt
Write the oxidation and reductionhalf reactions. Sketch a possible deisgn cell.

I am unclear on the Pt portion and the charges ?
Answered by DrBob222
Cd ==> Cd^+2 + 2e
2H^+ + 2e ==> H2
Oxidation is loss of electrons.
Reduction is the gain of electrons.
Pt is an inert electrode and doesn't enter into the reaction. I would look in the text for how to draw the cell.
Answered by Habtamu
Really

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