Question
caculate the number of atoms in 0.0340g zn
Answers
GPT-4o mini
To calculate the number of atoms in 0.0340 grams of zinc (Zn), you can follow these steps:
1. **Determine the molar mass of zinc**: The atomic mass of zinc is about 65.38 g/mol.
2. **Calculate the number of moles of zinc**: Use the formula:
\[
\text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}}
\]
\[
\text{Number of moles of Zn} = \frac{0.0340 \text{ g}}{65.38 \text{ g/mol}} \approx 0.000519 \text{ moles}
\]
3. **Convert moles to atoms**: Use Avogadro's number, which is approximately \( 6.022 \times 10^{23} \) atoms/mol.
\[
\text{Number of atoms} = \text{Number of moles} \times \text{Avogadro's number}
\]
\[
\text{Number of atoms} = 0.000519 \text{ moles} \times 6.022 \times 10^{23} \text{ atoms/mol} \approx 3.12 \times 10^{20} \text{ atoms}
\]
Therefore, there are approximately \( 3.12 \times 10^{20} \) atoms in 0.0340 grams of zinc.
1. **Determine the molar mass of zinc**: The atomic mass of zinc is about 65.38 g/mol.
2. **Calculate the number of moles of zinc**: Use the formula:
\[
\text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}}
\]
\[
\text{Number of moles of Zn} = \frac{0.0340 \text{ g}}{65.38 \text{ g/mol}} \approx 0.000519 \text{ moles}
\]
3. **Convert moles to atoms**: Use Avogadro's number, which is approximately \( 6.022 \times 10^{23} \) atoms/mol.
\[
\text{Number of atoms} = \text{Number of moles} \times \text{Avogadro's number}
\]
\[
\text{Number of atoms} = 0.000519 \text{ moles} \times 6.022 \times 10^{23} \text{ atoms/mol} \approx 3.12 \times 10^{20} \text{ atoms}
\]
Therefore, there are approximately \( 3.12 \times 10^{20} \) atoms in 0.0340 grams of zinc.