Systems of Linear Equations Unit Test

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Question
The Kesling Middle School PTA is planning a carnival to raise money for the school’s art department. They estimate that the event will be very popular and that they will have 500 people attend. They plan to charge adults $10 and children $5 for admission. The PTA wants to earn $3,500 from admission charges. How many adults and how many children need to attend for the PTA to reach their goal of $3,500?(1 point)
adults;
children

1 answer

To find how many adults and how many children need to attend for the PTA to reach their goal of $3,500, we can set up a system of equations.

Let:

  • \( a \) = the number of adults
  • \( c \) = the number of children

From the problem, we have the following information:

  1. The total number of attendees (adults + children) is 500: \[ a + c = 500 \quad \text{(1)} \]

  2. The total revenue from admissions should be $3,500. The charge is $10 per adult and $5 per child: \[ 10a + 5c = 3500 \quad \text{(2)} \]

Now we can solve this system of equations.

First, we can simplify equation (2) by dividing everything by 5: \[ 2a + c = 700 \quad \text{(3)} \]

Now we can use equations (1) and (3) to eliminate \( c \). From equation (1), we can express \( c \) in terms of \( a \): \[ c = 500 - a \]

Next, we substitute this expression for \( c \) into equation (3): \[ 2a + (500 - a) = 700 \]

Simplifying that gives: \[ 2a + 500 - a = 700 \] \[ a + 500 = 700 \] \[ a = 700 - 500 \] \[ a = 200 \]

Now that we have the number of adults, we can find \( c \): \[ c = 500 - a = 500 - 200 = 300 \]

Thus, the solution is:

  • Adults: 200
  • Children: 300

Final Answer: 200 adults; 300 children