Systems of Linear Equations Unit Test

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Question
Solve the system of equations.
4x−8y=−36

−6x+y=32
(1 point)
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1 answer

To solve the system of equations:

  1. \( 4x - 8y = -36 \)
  2. \( -6x + y = 32 \)

we can use either the substitution method, the elimination method, or graph the equations. Here, I will use the elimination method.

First, let's rearrange the second equation to express \( y \) in terms of \( x \):

\[ y = 6x + 32 \]

Now we can substitute this expression for \( y \) into the first equation:

\[ 4x - 8(6x + 32) = -36 \]

Distributing the \(-8\):

\[ 4x - 48x - 256 = -36 \]

Combine like terms:

\[ -44x - 256 = -36 \]

Add \( 256 \) to both sides:

\[ -44x = 220 \]

Now, divide by \(-44\):

\[ x = -5 \]

Now, substitute \( x = -5 \) back into the equation for \( y \):

\[ y = 6(-5) + 32 \] \[ y = -30 + 32 \] \[ y = 2 \]

Thus, the solution to the system of equations is:

\[ \boxed{(-5, 2)} \]