Question

Find the distance of Line C Your answer should be an integer.
ponit one is (-3,-10)
ponit two is (1,2)

Answer 1

To find the distance of the line defined by the two points \((-3, -10)\) and \((1, 2)\), we first need to calculate the distance between these two points. The distance \(d\) between two points \((x_1, y_1)\) and \((x_2, y_2)\) can be calculated using the distance formula:

\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]

Here, point one is \((-3, -10)\) and point two is \((1, 2)\). Using the coordinates:

- \(x_1 = -3\)
- \(y_1 = -10\)
- \(x_2 = 1\)
- \(y_2 = 2\)

Now, we can plug these values into the distance formula:

\[
d = \sqrt{(1 - (-3))^2 + (2 - (-10))^2}
\]

This simplifies to:

\[
d = \sqrt{(1 + 3)^2 + (2 + 10)^2}
\]
\[
d = \sqrt{(4)^2 + (12)^2}
\]
\[
d = \sqrt{16 + 144}
\]
\[
d = \sqrt{160}
\]

Now we simplify \(\sqrt{160}\):

\[
\sqrt{160} = \sqrt{16 \times 10} = \sqrt{16} \times \sqrt{10} = 4\sqrt{10}
\]

If you want the approximate decimal value of \(d\):

\[
4\sqrt{10} \approx 4 \times 3.162 = 12.648
\]

However, if you're to provide an integer answer, we'll take the nearest integer value of \(d\):

\[
d \approx 13
\]

So, the distance between the two points, expressed as an integer, is:

\[
\boxed{13}
\]