To determine which crosses have a greater probability of producing Chihuahuas with the long-hair trait than the Hh x Hh cross, we first need to understand the inheritance pattern for the hair length trait in Chihuahuas.
- Let's assume:
- H = allele for long hair (dominant)
- h = allele for short hair (recessive)
In the cross Hh x Hh:
- The possible genotypes are:
- HH (25%)
- Hh (50%)
- hh (25%)
This results in a 75% probability of producing a puppy with long hair (HH or Hh).
Now, let's analyze each of the other crosses based on their genotypes:
-
Hh x hh:
- Possible genotypes:
- Hh (50%)
- hh (50%)
- Probability of long hair (Hh) = 50%.
- Possible genotypes:
-
hh x hh:
- Possible genotypes:
- hh (100%)
- Probability of long hair = 0%.
- Possible genotypes:
-
HH x Hh:
- Possible genotypes:
- HH (50%)
- Hh (50%)
- Probability of long hair (HH or Hh) = 100%.
- Possible genotypes:
Now, comparing all these probabilities to the Hh x Hh cross (75%):
- Hh x hh = 50% (less than 75%)
- hh x hh = 0% (less than 75%)
- HH x Hh = 100% (greater than 75%)
From this analysis, the crosses that have a greater probability of producing Chihuahuas with the long-hair trait than the Hh x Hh cross are:
- HH x Hh
Therefore, the answer is:
HH x Hh