Which other crosses have a greater probability of producing Chihuahuas with the long-hair trait than the Hh x Hh cross? Select all that apply.

Group of answer choices

None of these crosses

Hh x hh

hh x hh

HH x. Hh

1 answer

To determine which crosses have a greater probability of producing Chihuahuas with the long-hair trait than the Hh x Hh cross, we first need to understand the inheritance pattern for the hair length trait in Chihuahuas.

  • Let's assume:
    • H = allele for long hair (dominant)
    • h = allele for short hair (recessive)

In the cross Hh x Hh:

  • The possible genotypes are:
    • HH (25%)
    • Hh (50%)
    • hh (25%)

This results in a 75% probability of producing a puppy with long hair (HH or Hh).

Now, let's analyze each of the other crosses based on their genotypes:

  1. Hh x hh:

    • Possible genotypes:
      • Hh (50%)
      • hh (50%)
    • Probability of long hair (Hh) = 50%.
  2. hh x hh:

    • Possible genotypes:
      • hh (100%)
    • Probability of long hair = 0%.
  3. HH x Hh:

    • Possible genotypes:
      • HH (50%)
      • Hh (50%)
    • Probability of long hair (HH or Hh) = 100%.

Now, comparing all these probabilities to the Hh x Hh cross (75%):

  • Hh x hh = 50% (less than 75%)
  • hh x hh = 0% (less than 75%)
  • HH x Hh = 100% (greater than 75%)

From this analysis, the crosses that have a greater probability of producing Chihuahuas with the long-hair trait than the Hh x Hh cross are:

  • HH x Hh

Therefore, the answer is:

HH x Hh