Based on the Punnett square modeling the cross of two Hh Chihuahuas, what percentage of Chihuahua puppies should the breeder expect to have long hair?

Question

Group of answer choices

50%

75%

100%

25%

Answer 1

In a Punnett square for the cross of two heterozygous Chihuahuas (Hh), where "H" represents the allele for long hair (dominant) and "h" represents the allele for short hair (recessive), we can set up the following:

• Possible gametes from each parent: H and h from the first Chihuahua, and H and h from the second Chihuahua.

The Punnett square would look like this:

        H       h
      ------------
H |    HH    |     Hh    |
      ------------
h |    Hh    |     hh    |
      ------------

From the square, we can see the following genotypes of the offspring:

• 1 HH (homozygous dominant, long hair)
• 2 Hh (heterozygous, long hair)
• 1 hh (homozygous recessive, short hair)

Now, we count the percentage of puppies with long hair (either HH or Hh):

• Total long hair: 1 (HH) + 2 (Hh) = 3
• Total offspring: 4

Percentage of puppies with long hair = (Number with long hair / Total number of offspring) × 100 = (3/4) × 100 = 75%

So, the breeder should expect 75% of Chihuahua puppies to have long hair.