Asked by Amy~
A compound that contains only Fe and O is 69.9% Fe by mass. What is the empirical formula of theis compound?
Attempt: 69.9g(1/56): 1
30.1g(1/16): 2
I got FeO2
but the answers say that it is Fe2O3
Attempt: 69.9g(1/56): 1
30.1g(1/16): 2
I got FeO2
but the answers say that it is Fe2O3
Answers
Answered by
Amy~
I got it since O comes out to be 1.5 * 2 = 3
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