Asked by hi
Which expression is equivalent to (36x ^ 4 * y ^ 5)/((3xy) ^ 2) defined? for all values of x and y where the expression is
Q
J 6x ^ 3 * y ^ 4
Η 4x ^ 2 * y ^ 3
F 12x ^ 3 * y ^ 4
G 27x ^ 2 * y ^ 3
Q
J 6x ^ 3 * y ^ 4
Η 4x ^ 2 * y ^ 3
F 12x ^ 3 * y ^ 4
G 27x ^ 2 * y ^ 3
Answers
Answered by
GPT-4o mini
To simplify the given expression \((36x^4y^5) / ((3xy)^2)\), we first simplify the denominator \((3xy)^2\):
\[
(3xy)^2 = (3^2)(x^2)(y^2) = 9x^2y^2
\]
Now we can rewrite the original expression:
\[
\frac{36x^4y^5}{9x^2y^2}
\]
Next, we simplify the fraction by dividing both the numerator and the denominator by their common factors:
1. **Numerical Coefficient:**
\[
\frac{36}{9} = 4
\]
2. **For \(x\) terms:**
\[
\frac{x^4}{x^2} = x^{4-2} = x^2
\]
3. **For \(y\) terms:**
\[
\frac{y^5}{y^2} = y^{5-2} = y^3
\]
Now, putting it all together, we have:
\[
\frac{36x^4y^5}{9x^2y^2} = 4x^2y^3
\]
Thus, the simplified expression is:
\[
4x^2y^3
\]
So the expression \( (36x^4 y^5) / ((3xy)^2) \) simplifies to **\( 4x^2y^3 \)**, which corresponds to option **Η**.
\[
(3xy)^2 = (3^2)(x^2)(y^2) = 9x^2y^2
\]
Now we can rewrite the original expression:
\[
\frac{36x^4y^5}{9x^2y^2}
\]
Next, we simplify the fraction by dividing both the numerator and the denominator by their common factors:
1. **Numerical Coefficient:**
\[
\frac{36}{9} = 4
\]
2. **For \(x\) terms:**
\[
\frac{x^4}{x^2} = x^{4-2} = x^2
\]
3. **For \(y\) terms:**
\[
\frac{y^5}{y^2} = y^{5-2} = y^3
\]
Now, putting it all together, we have:
\[
\frac{36x^4y^5}{9x^2y^2} = 4x^2y^3
\]
Thus, the simplified expression is:
\[
4x^2y^3
\]
So the expression \( (36x^4 y^5) / ((3xy)^2) \) simplifies to **\( 4x^2y^3 \)**, which corresponds to option **Η**.
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