You use scale factor of 3/4

to create a dilated circle with a radius of 9 inches. What is the radius of the original circle?

1 answer

To find the radius of the original circle when a scale factor of \( \frac{3}{4} \) is applied to a circle with a radius of 9 inches, you can use the relationship between the radius of the original circle (denote it as \( r \)) and the radius of the dilated circle (which is given as 9 inches).

The relationship can be expressed as follows:

\[ \text{Dilated radius} = \text{Original radius} \times \text{Scale factor} \]

Substituting the known values:

\[ 9 = r \times \frac{3}{4} \]

To solve for \( r \), you can rearrange the equation:

\[ r = \frac{9}{\frac{3}{4}} \]

Dividing by a fraction is the same as multiplying by its reciprocal:

\[ r = 9 \times \frac{4}{3} \]

Now calculate \( r \):

\[ r = 9 \times \frac{4}{3} = \frac{36}{3} = 12 \]

Thus, the radius of the original circle is \( \boxed{12} \) inches.