Question

Write the condensed electron configuration and partial orbital diagram from organized energy level of Ga3+

Answer 1

The electron configuration of gallium (Ga) in its neutral state (atomic number 31) is:

\[
\text{[Ar]} 4s^2 3d^{10} 4p^1
\]

When gallium loses three electrons to form \( \text{Ga}^{3+} \), the electrons are removed from the outermost energy levels first. The electrons will be removed from the 4p and 4s orbitals before the 3d orbital.

Thus, the electron configuration for \( \text{Ga}^{3+} \) is:

\[
\text{[Ar]} 3d^{10}
\]

Now, let's summarize the electron configuration for \( \text{Ga}^{3+} \):
- **Condensed Electron Configuration:** \([Ar] 3d^{10}\)

### Partial Orbital Diagram for \( \text{Ga}^{3+} \)

In the partial orbital diagram, we only need to represent the orbitals that contain electrons for \( \text{Ga}^{3+} \). The 3d subshell has 10 electrons, which means it is fully filled:

```
3d: ↑↓ ↑↓ ↑↓ ↑↓ ↑↓
```

This diagram represents that each of the five 3d orbitals is filled with two electrons, indicating that all 10 electrons are in the 3d subshell.

### Summary
- **Condensed Electron Configuration:** \([Ar] 3d^{10}\)
- **Partial Orbital Diagram:**
```
3d: ↑↓ ↑↓ ↑↓ ↑↓ ↑↓
```