Question

Use the image to answer the question.

A coordinate plane shows a graph of an upward-sloping, diagonal, dashed line, with shading extending from the line to the left. The line starts in quadrant 3, extends through quadrant 4, and ends in quadrant 1.

Is the point (12,−112)
a solution to the inequality y>45x−3
, as shown on the graph? Enter 1 for yes or 2 for no.

Answer 1

i typed it in and it was wrong it is really YES

Answer 2

To determine if the point (12, -112) is a solution to the inequality \( y > 45x - 3 \), we need to substitute \( x = 12 \) into the equation \( y = 45x - 3 \) and see if the corresponding \( y \) value is less than -112.

1. Substitute \( x = 12 \) into \( y = 45x - 3 \):
\[
y = 45(12) - 3
\]

2. Calculate \( 45(12) \):
\[
45 \times 12 = 540
\]

3. Now calculate \( 540 - 3 \):
\[
540 - 3 = 537
\]

Now, we compare the resulting \( y \) value (537) to the y-coordinate of the point (-112):

- The inequality is \( y > 537 \).

Since -112 is less than 537, it does not satisfy the inequality. Therefore, the point (12, -112) is not a solution to the inequality \( y > 45x - 3 \).

The answer is **2** (no).