Question
What is the volume of the cone. Height is 9 in and the radius is 5 in. Use 3.14 for pi.
423.9
47.1
235.5
942
423.9
47.1
235.5
942
Answers
GPT-4o mini
The formula for the volume \( V \) of a cone is given by:
\[
V = \frac{1}{3} \pi r^2 h
\]
where \( r \) is the radius and \( h \) is the height. Given that the radius \( r = 5 \) inches and the height \( h = 9 \) inches, we can plug in the values:
\[
V = \frac{1}{3} \times 3.14 \times (5)^2 \times 9
\]
Calculating \( (5)^2 \):
\[
(5)^2 = 25
\]
Now substituting back into the volume formula:
\[
V = \frac{1}{3} \times 3.14 \times 25 \times 9
\]
Calculating \( 25 \times 9 \):
\[
25 \times 9 = 225
\]
Now substituting that back in:
\[
V = \frac{1}{3} \times 3.14 \times 225
\]
Calculating \( 3.14 \times 225 \):
\[
3.14 \times 225 = 706.5
\]
Now dividing by 3:
\[
V = \frac{706.5}{3} = 235.5
\]
Therefore, the volume of the cone is:
\[
\boxed{235.5}
\]
\[
V = \frac{1}{3} \pi r^2 h
\]
where \( r \) is the radius and \( h \) is the height. Given that the radius \( r = 5 \) inches and the height \( h = 9 \) inches, we can plug in the values:
\[
V = \frac{1}{3} \times 3.14 \times (5)^2 \times 9
\]
Calculating \( (5)^2 \):
\[
(5)^2 = 25
\]
Now substituting back into the volume formula:
\[
V = \frac{1}{3} \times 3.14 \times 25 \times 9
\]
Calculating \( 25 \times 9 \):
\[
25 \times 9 = 225
\]
Now substituting that back in:
\[
V = \frac{1}{3} \times 3.14 \times 225
\]
Calculating \( 3.14 \times 225 \):
\[
3.14 \times 225 = 706.5
\]
Now dividing by 3:
\[
V = \frac{706.5}{3} = 235.5
\]
Therefore, the volume of the cone is:
\[
\boxed{235.5}
\]