Question

A cubic foot of water is about 7.48 gallons. How many gallons of water would be needed to fill the rectangular pool to 91% capacity? Click HERE for Help Video
the hight is 5 feet
the base is 28 feet
and the other side is 8 feet



(1 point)
The pool will require
gallons of water (Round to the tenths place)

Answer 1

To find out how many gallons of water are needed to fill the rectangular pool to 91% capacity, we first calculate the volume of the pool in cubic feet and then convert that volume to gallons.

1. **Calculate the volume of the pool in cubic feet**:
\[
\text{Volume} = \text{height} \times \text{base} \times \text{other side} = 5 \, \text{feet} \times 28 \, \text{feet} \times 8 \, \text{feet}
\]
\[
\text{Volume} = 5 \times 28 \times 8 = 1120 \, \text{cubic feet}
\]

2. **Calculate 91% of the volume**:
\[
\text{Volume at 91%} = 0.91 \times 1120 = 1019.2 \, \text{cubic feet}
\]

3. **Convert the volume from cubic feet to gallons**:
Since 1 cubic foot is about 7.48 gallons:
\[
\text{Gallons} = 1019.2 \, \text{cubic feet} \times 7.48 \, \text{gallons/cubic foot}
\]
\[
\text{Gallons} = 1019.2 \times 7.48 \approx 7615.34 \, \text{gallons}
\]

4. **Round to the tenths place**:
The final result is approximately:
\[
\text{Gallons} \approx 7615.3
\]

Therefore, the pool will require **7615.3 gallons** of water to fill to 91% capacity.