Theequationoflinemis

y
=
23
x

2
85
. The
equationoflinenisy = 23x + 60
. Are
linemandlinenparallelorperpendicular?

1 answer

To determine whether the lines represented by the equations \( y = \frac{23}{2} x - \frac{285}{100} \) and \( y = 23x + 60 \) are parallel or perpendicular, we first need to identify their slopes.

  1. Finding the slope of the first line: The equation given is \( y = \frac{23}{2} x - \frac{285}{100} \).

    • The slope (m₁) of this line is \( \frac{23}{2} \).
  2. Finding the slope of the second line: The equation is \( y = 23x + 60 \).

    • The slope (m₂) of this line is \( 23 \).
  3. Comparing the slopes: Because the two slopes are compared, we check:

    • For the lines to be parallel, their slopes must be equal, which means \( m₁ = m₂ \).
    • For the lines to be perpendicular, the product of their slopes must equal \(-1\), which means \( m₁ \cdot m₂ = -1 \).

Let's compute the product of the slopes: \[ \frac{23}{2} \cdot 23 = \frac{23 \cdot 23}{2} = \frac{529}{2} \]

Since \( \frac{529}{2} \) is not equal to \(-1\), the lines are not perpendicular.

Next, let's compare the slopes: \[ \frac{23}{2} \text{ (which is 11.5) is not equal to } 23. \]

Since \( \frac{23}{2} \) is not equal to \( 23 \), the lines are not parallel.

Conclusion: The lines are neither parallel nor perpendicular.