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Original Question
Line m passes through points (4, 9) and (2, 2). Line n passes through points (2, 2) and (6, 7). Are line m and line n parallel...Asked by burnout
Line a passes through points (1, 18) and (10, 10). Line b passes through points (9, 10) and (1, 1). Are line a and line b parallel or perpendicular?
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Answered by
GPT-4o mini
To determine if the lines are parallel or perpendicular, we will first find the slopes of both lines.
**Slope of Line A:**
Line A passes through points (1, 18) and (10, 10). The slope \( m_A \) is calculated using the formula:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Substituting the coordinates of the points:
\[
m_A = \frac{10 - 18}{10 - 1} = \frac{-8}{9}
\]
**Slope of Line B:**
Line B passes through points (9, 10) and (1, 1). The slope \( m_B \) is calculated similarly:
\[
m_B = \frac{1 - 10}{1 - 9} = \frac{-9}{-8} = \frac{9}{8}
\]
**Determine Relationship between the Slopes:**
Two lines are parallel if their slopes are equal and perpendicular if the product of their slopes is -1.
To check if they are perpendicular:
\[
m_A \cdot m_B = \left(-\frac{8}{9}\right) \cdot \left(\frac{9}{8}\right)
\]
Calculating the product:
\[
m_A \cdot m_B = -\frac{8 \cdot 9}{9 \cdot 8} = -1
\]
Since the product of the slopes is -1, this means that Line A and Line B are **perpendicular**.
**Slope of Line A:**
Line A passes through points (1, 18) and (10, 10). The slope \( m_A \) is calculated using the formula:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Substituting the coordinates of the points:
\[
m_A = \frac{10 - 18}{10 - 1} = \frac{-8}{9}
\]
**Slope of Line B:**
Line B passes through points (9, 10) and (1, 1). The slope \( m_B \) is calculated similarly:
\[
m_B = \frac{1 - 10}{1 - 9} = \frac{-9}{-8} = \frac{9}{8}
\]
**Determine Relationship between the Slopes:**
Two lines are parallel if their slopes are equal and perpendicular if the product of their slopes is -1.
To check if they are perpendicular:
\[
m_A \cdot m_B = \left(-\frac{8}{9}\right) \cdot \left(\frac{9}{8}\right)
\]
Calculating the product:
\[
m_A \cdot m_B = -\frac{8 \cdot 9}{9 \cdot 8} = -1
\]
Since the product of the slopes is -1, this means that Line A and Line B are **perpendicular**.
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