Question

Question solve
6^4-7x^2+2=0
MY ANSWER
I get 28b^13+b^2+22b+26 over 4b+3
but I do not understand how this can be the solution for x

Answer 1

I don't either!
You have probably looked up the answer for the wrong question.
Also, shouldn't the original question be:
6x^4-7x^2+2=0
instead of
6^4-7x^2+2=0 ?

If that's the case, think of
y=x² and rewrite the question in terms of y.

Answer 2

6x^4-7x^2+2=0
is it 2^1/2 over 3^1/2

Answer 3

Solve means to find the value of the unknown variable, namely x.

6x^4-7x^2+2=0 can be factorized as
(2x²-1)(3²-2)=0
So you would equate each factor to zero to find the roots (4 roots in all).
For example,
(2x²-1)=0
2x²=1
x²=(1/2)
x=±(&radic(2)/2)
I'll leave it to you to find the other two roots.

Answer 4

(2x²-1)(3²-2)=0 should read
(2x²-1)(3x²-2)=0,
and √(2/3) <i>is</i> one of the remaining roots.