What is the volume of a shoebox that is 1 1/2

1
1
2
ft. long, 3/4
3
4
ft. wide, and 1/2
1
2
ft. tall? Apply the V=BƗh
š‘‰
=
šµ
Ɨ
ā„Ž
formula to solve.(1 point)
Responses

9/16 ft.3
9
16
ft.
3
Start Fraction 9 over 16 end fraction ft cubed

3/4 ft.3
3
4
ft
.
3
Start Fraction 3 over 4 end fraction ft cubed

2 3/4 ft.3
2
3
4
ft.
3
2 Start Fraction 3 over 4 end fraction ft cubed

1 1/8 ft.3
1
1
8
ft.
3
1 Start Fraction 1 over 8 end fraction ft cubed

1 answer

To find the volume of the shoebox using the formula \( V = B \times h \), we first need to calculate the area of the base \( B \) and then multiply it by the height \( h \).

Step 1: Calculate the area of the base \( B \)

The base is a rectangle with the following dimensions:

  • Length = \( 1 \frac{1}{2} \) ft = \( \frac{3}{2} \) ft
  • Width = \( \frac{3}{4} \) ft

The area of the base \( B \) is calculated as follows:

\[ B = \text{Length} \times \text{Width} = \frac{3}{2} \times \frac{3}{4} \]

To multiply the fractions:

\[ B = \frac{3 \times 3}{2 \times 4} = \frac{9}{8} \quad \text{(square feet)} \]

Step 2: Height of the shoebox \( h \)

Height \( h = \frac{1}{2} \) ft.

Step 3: Calculate the volume \( V \)

Now use the formula for volume:

\[ V = B \times h = \frac{9}{8} \times \frac{1}{2} \]

To multiply the fractions:

\[ V = \frac{9 \times 1}{8 \times 2} = \frac{9}{16} \quad \text{(cubic feet)} \]

Thus, the volume of the shoebox is

\[ \frac{9}{16} \text{ ft}^3 \]

So the correct response is:

9/16 ft³