Question

What is the volume of a shipping container that is 20 1/2
20
1
2
ft. long, 12 1/4
12
1
4
ft. wide, and 8 1/4
8
1
4
ft. tall? Apply the V=B×h
𝑉
=
𝐵
×
ℎ
formula to solve.(1 point)
Responses

2,071 25/32 ft.3
2
,
071
25
32

ft.
3
2,071 Start Fraction 25 over 32 End Fraction ft cubed

251 1/8 ft.3
251
1
8

ft.
3
251 Start Fraction 1 over 8 end fraction ft cubed

41 ft.3
41

ft.
3
41 ft cubed

169 1/8 ft.3

Answer 1

To find the volume of the shipping container, we need to apply the formula \( V = B \times h \), where \( B \) is the base area and \( h \) is the height.

First, calculate the base area \( B \):
- Length = \( 20 \frac{1}{2} \) ft = \( 20.5 \) ft
- Width = \( 12 \frac{1}{4} \) ft = \( 12.25 \) ft

Now calculate the base area \( B \):
\[
B = \text{Length} \times \text{Width} = 20.5 \, \text{ft} \times 12.25 \, \text{ft}
\]

Calculating \( 20.5 \times 12.25 \):
\[
B = 20.5 \times 12.25 = 250.625 \, \text{ft}^2
\]

Next, the height \( h \) is given as \( 8 \frac{1}{4} \) ft = \( 8.25 \) ft.

Now calculate the volume \( V \):
\[
V = B \times h = 250.625 \, \text{ft}^2 \times 8.25 \, \text{ft}
\]

Calculating \( 250.625 \times 8.25 \):
\[
V = 250.625 \times 8.25 = 2061.15625 \, \text{ft}^3
\]

Now, converting \( 2061.15625 \) into a mixed fraction:
To find the fraction part:
\[
2061.15625 = 2061 + 0.15625
\]

Now converting \( 0.15625 \) to a fraction:
\[
0.15625 = \frac{25}{160} = \frac{5}{32}
\]

Thus, \( 2061.15625 = 2061 \frac{5}{32} \) ft³.

Since the options provided did not seem to match this answer, perhaps there is an issue with the calculations or the choices given; nonetheless, the correct volume is approximately:

\[
\text{Volume} = 2061 \frac{5}{32}\, \text{ft}^3 \approx 2061.15625 \, \text{ft}^3
\]

Please confirm whether the given options are complete or if any calculations should be re-evaluated based on the context!