Question

The best player on a basketball team makes 85​% of all free throws. The​ second-best player makes 75​% of all free throws. The​ third-best player makes 65​% of all free throws. Based on their experimental​ probabilities, estimate the number of free throws each player will make in his or her next 40 attempts. Explain.
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Part 1
For the best​ player, one equation that gives the estimated number of free throws is
StartFraction 85 Over 100 EndFraction equals StartFraction x Over 40 EndFraction .
The best player will make about
  
34 free throws.
Part 2
For the​ second-best player, one equation that gives the estimated number of free throws is
StartFraction 75 Over 100 EndFraction equals StartFraction y Over 40 EndFraction .
The​ second-best player will make about
  
30 free throws.
Part 3
For the​ third-best player, one equation that gives the estimated number of free throws is
StartFraction 65 Over 100 EndFraction equals StartFraction 40 Over z EndFraction .
The​ third-best player will make about
  
enter your response here free throws.

Answer 1

To estimate the number of free throws the third-best player will make in their next 40 attempts, we can set up a proportion similar to the previous parts.

**Part 3:**
For the third-best player, who makes 65% of all free throws, we can set up the equation:
\[
\frac{65}{100} = \frac{z}{40}
\]

Now we can solve for \(z\) (the number of free throws the third-best player is expected to make).

1. Cross-multiply:
\[
65 \cdot 40 = 100 \cdot z
\]
\[
2600 = 100z
\]

2. Next, divide both sides by 100:
\[
z = \frac{2600}{100} = 26
\]

So, the third-best player will make about **26 free throws** in their next 40 attempts.