Question
There are 62 phones in an office building.
How many unique connections between two of these phones can be made?
How many unique connections between two of these phones can be made?
Answers
GPT-4o mini
To find the number of unique connections between two phones, we can use the concept of combinations. Since a connection between two phones does not depend on the order in which the phones are chosen, we need to calculate the number of ways to choose 2 phones from 62 phones.
The formula for combinations \( C(n, r) \) is given by:
\[
C(n, r) = \frac{n!}{r!(n - r)!}
\]
where
- \( n \) is the total number of items,
- \( r \) is the number of items to choose, and
- \( ! \) denotes factorial, the product of all positive integers up to that number.
In this case, \( n = 62 \) (the number of phones), and \( r = 2 \) (the number of phones we want to connect).
Using the formula:
\[
C(62, 2) = \frac{62!}{2!(62 - 2)!} = \frac{62!}{2! \cdot 60!}
\]
This simplifies as follows:
\[
= \frac{62 \times 61 \times 60!}{2! \times 60!}
\]
The \( 60! \) in the numerator and denominator cancels out:
\[
= \frac{62 \times 61}{2!}
\]
Calculating \( 2! \):
\[
2! = 2 \times 1 = 2
\]
Now substituting that back into our equation:
\[
= \frac{62 \times 61}{2} = \frac{3782}{2} = 1891
\]
Thus, the number of unique connections between two of the 62 phones is \( \boxed{1891} \).
The formula for combinations \( C(n, r) \) is given by:
\[
C(n, r) = \frac{n!}{r!(n - r)!}
\]
where
- \( n \) is the total number of items,
- \( r \) is the number of items to choose, and
- \( ! \) denotes factorial, the product of all positive integers up to that number.
In this case, \( n = 62 \) (the number of phones), and \( r = 2 \) (the number of phones we want to connect).
Using the formula:
\[
C(62, 2) = \frac{62!}{2!(62 - 2)!} = \frac{62!}{2! \cdot 60!}
\]
This simplifies as follows:
\[
= \frac{62 \times 61 \times 60!}{2! \times 60!}
\]
The \( 60! \) in the numerator and denominator cancels out:
\[
= \frac{62 \times 61}{2!}
\]
Calculating \( 2! \):
\[
2! = 2 \times 1 = 2
\]
Now substituting that back into our equation:
\[
= \frac{62 \times 61}{2} = \frac{3782}{2} = 1891
\]
Thus, the number of unique connections between two of the 62 phones is \( \boxed{1891} \).