To find the lower quartile, median, and upper quartile of the data set \(3345577889\), we can follow these steps:
-
Arrange the data in ascending order (though it already appears to be sorted):
- The data set: \(3, 3, 4, 5, 5, 7, 7, 8, 8, 9, 9\)
-
Count the number of data points:
- There are 11 data points.
-
Calculate the median (the middle value):
- Since there are 11 numbers, the median is the value at position \(\frac{n + 1}{2} = \frac{11 + 1}{2} = 6\). So, the median is the 6th number in the ordered list.
- Median = \(7\) (the 6th number)
-
Calculate the lower quartile (Q1):
- Q1 is the median of the first half of the data (the lower 50%). The first half is \(3, 3, 4, 5, 5\) (the first five numbers).
- Q1 is the median of this set. For 5 numbers, the median is the 3rd number, which is \(4\).
-
Calculate the upper quartile (Q3):
- Q3 is the median of the second half of the data (the upper 50%). The second half is \(7, 7, 8, 8, 9, 9\) (the last five numbers).
- The upper half is \(7, 7, 8, 8, 9, 9\). Since there are 6 numbers, the median is calculated as the average of the 3rd and 4th numbers.
- Q3 = \(\frac{8 + 8}{2} = 8\).
Now, we can summarize the results:
- Lower quartile (Q1) = \(4\)
- Median = \(7\)
- Upper quartile (Q3) = \(8\)
Final Results:
- Lower quartile = 4
- Median = 7
- Upper quartile = 8