To determine the force with which the softball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force \( F \) is equal to mass \( m \) multiplied by acceleration \( a \):
\[ F = m \cdot a \]
Given:
- Mass of the softball, \( m = 0.2 \) kg
- Acceleration of the softball, \( a = 8 \) m/s²
Now, substituting the values into the equation:
\[ F = 0.2 , \text{kg} \cdot 8 , \text{m/s}^2 = 1.6 , \text{N} \]
Thus, the force with which the ball will hit the catcher's mitt is 1.6 N.
The correct answer is: 4. 1.6 N