Question

Constantinos is painting a rectangular outline of a frame on the wall, leaving the area inside unpainted. He wants the outside of the frame to be 9 ft. wide by 12 ft. tall. The inside of the frame will be 6 ft. wide by 10 ft. tall. Calculate the area of the frame.(1 point)
Responses

108 ft.2
108 ft. squared

60 ft.2
60 ft. squared

168 ft.2
168 ft. squared

48 ft.2

Answer 1

To calculate the area of the frame, we need to find the area of the outer rectangle and subtract the area of the inner rectangle.

1. **Calculate the area of the outer rectangle (width = 9 ft, height = 12 ft):**
\[
\text{Area of outer rectangle} = \text{width} \times \text{height} = 9 \text{ ft} \times 12 \text{ ft} = 108 \text{ ft}^2
\]

2. **Calculate the area of the inner rectangle (width = 6 ft, height = 10 ft):**
\[
\text{Area of inner rectangle} = \text{width} \times \text{height} = 6 \text{ ft} \times 10 \text{ ft} = 60 \text{ ft}^2
\]

3. **Calculate the area of the frame:**
\[
\text{Area of frame} = \text{Area of outer rectangle} - \text{Area of inner rectangle} = 108 \text{ ft}^2 - 60 \text{ ft}^2 = 48 \text{ ft}^2
\]

Thus, the area of the frame is \(48 \text{ ft}^2\).

The answer is: **48 ft.²** (48 ft. squared).