Triangle ABC has vertices point A (-2,-2), point B (-4, -3), and point C (-2,-5) Find the coordinates of A', B', and C' after a dilation with a scale factor of 3 and a center point of dilation at the origin. (2 points)

A' = (___,___)

B' = (___,___)

C' = (___,___)

1 answer

To find the coordinates of points A', B', and C' after a dilation with a scale factor of 3 from the origin, we can use the formula for dilation:

\[ (x', y') = (k \cdot x, k \cdot y) \]

where \((x, y)\) are the original coordinates, \(k\) is the scale factor, and \((x', y')\) are the new coordinates after dilation.

Given points:

  • A (-2, -2)
  • B (-4, -3)
  • C (-2, -5)

We will apply the dilation for each point.

  1. Dilation of point A (-2, -2): \[ A' = (3 \cdot -2, 3 \cdot -2) = (-6, -6) \]

  2. Dilation of point B (-4, -3): \[ B' = (3 \cdot -4, 3 \cdot -3) = (-12, -9) \]

  3. Dilation of point C (-2, -5): \[ C' = (3 \cdot -2, 3 \cdot -5) = (-6, -15) \]

Now, we can summarize the new coordinates:

  • A' = (-6, -6)
  • B' = (-12, -9)
  • C' = (-6, -15)

Thus, the final answers are:

A' = (-6, -6)

B' = (-12, -9)

C' = (-6, -15)