Use the image to answer the question. A researcher is testing a new fertilizer to determine whether it encourages plant growth. One group of oak tree saplings is treated weekly with the new fertilizer, while another group of oak tree saplings is not. Their heights are recorded weekly. After 10 weeks, the results are compared. The researcher finds that the average difference in the heights of the fertilized saplings versus the nonfertilized saplings is 1.5 centimeters. She then generates a simulation of 96 more trials. Examine the histogram of the simulation of differences. Do the data and the simulations provide evidence that the fertilizer has encouraged growth? (1 point) Responses The data and simulations show evidence that the fertilizer encourages growth. The average height falls in the bin near the center of the distribution, between 0–2, indicating that the difference is not unusual. The data and simulations show evidence that the fertilizer encourages growth. The average height falls in the bin near the center of the distribution, between 0–2, indicating that the difference is not unusual. The data and simulations show no evidence that the fertilizer encourages growth. The average height falls in the bin near the center of the distribution, between 0–2, indicating that the difference is unusual. The data and simulations show no evidence that the fertilizer encourages growth. The average height falls in the bin near the center of the distribution, between 0–2, indicating that the difference is unusual. The data and simulations show evidence that the fertilizer encourages growth. The average height falls in the bin near the center of the distribution, between 0–2, indicating that the difference is unusual. The data and simulations show evidence that the fertilizer encourages growth. The average height falls in the bin near the center of the distribution, between 0–2, indicating that the difference is unusual. The data and simulations show no evidence that the fertilizer encourages growth. The average height falls in the bin near the center of the distribution, between 0–2, indicating that the difference is not unusual.

asked by N

2 months ago

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1 answer

To determine whether the fertilizer has encouraged growth based on the information provided, we need to analyze the average difference in heights between the fertilized and non-fertilized saplings (1.5 cm) and how it relates to the histogram of the simulations.

If the average height difference of 1.5 cm falls in the center of the distribution (between 0–2 cm) of the simulation data, it suggests that this difference is within the range of expected variability when no real effect exists, indicating that the observed growth may be due to random chance rather than the effect of the fertilizer.

Considering this logic, the appropriate response would be:

The data and simulations show no evidence that the fertilizer encourages growth. The average height falls in the bin near the center of the distribution, between 0–2, indicating that the difference is not unusual.

This answer reflects the interpretation that if the average difference is not unusual according to the simulation, then the fertilizer effect cannot be conclusively claimed.

answered by GPT-4o mini

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Question

Use the image to answer the question. A researcher is testing a new fertilizer to determine whether it encourages plant growth. One group of oak tree saplings is treated weekly with the new fertilizer, while another group of oak tree saplings is not. Their heights are recorded weekly. After 10 weeks, the results are compared. The researcher finds that the average difference in the heights of the fertilized saplings versus the nonfertilized saplings is 1.5 centimeters. She then generates a simulation of 96 more trials. Examine the histogram of the simulation of differences. Do the data and the simulations provide evidence that the fertilizer has encouraged growth? (1 point) Responses The data and simulations show evidence that the fertilizer encourages growth. The average height falls in the bin near the center of the distribution, between 0–2, indicating that the difference is not unusual. The data and simulations show evidence that the fertilizer encourages growth. The average height falls in the bin near the center of the distribution, between 0–2, indicating that the difference is not unusual. The data and simulations show no evidence that the fertilizer encourages growth. The average height falls in the bin near the center of the distribution, between 0–2, indicating that the difference is unusual. The data and simulations show no evidence that the fertilizer encourages growth. The average height falls in the bin near the center of the distribution, between 0–2, indicating that the difference is unusual. The data and simulations show evidence that the fertilizer encourages growth. The average height falls in the bin near the center of the distribution, between 0–2, indicating that the difference is unusual. The data and simulations show evidence that the fertilizer encourages growth. The average height falls in the bin near the center of the distribution, between 0–2, indicating that the difference is unusual. The data and simulations show no evidence that the fertilizer encourages growth. The average height falls in the bin near the center of the distribution, between 0–2, indicating that the difference is not unusual.

1 answer

To determine whether the fertilizer has encouraged growth based on the information provided, we need to analyze the average difference in heights between the fertilized and non-fertilized saplings (1.5 cm) and how it relates to the histogram of the simulations.

If the average height difference of 1.5 cm falls in the center of the distribution (between 0–2 cm) of the simulation data, it suggests that this difference is within the range of expected variability when no real effect exists, indicating that the observed growth may be due to random chance rather than the effect of the fertilizer.

Considering this logic, the appropriate response would be:

The data and simulations show no evidence that the fertilizer encourages growth. The average height falls in the bin near the center of the distribution, between 0–2, indicating that the difference is not unusual.

This answer reflects the interpretation that if the average difference is not unusual according to the simulation, then the fertilizer effect cannot be conclusively claimed.

GPT-4o mini · Answer

To determine whether the fertilizer has encouraged growth based on the information provided, we need to analyze the average difference in heights between the fertilized and non-fertilized saplings (1.5 cm) and how it relates to the histogram of the simulations.

If the average height difference of 1.5 cm falls in the center of the distribution (between 0–2 cm) of the simulation data, it suggests that this difference is within the range of expected variability when no real effect exists, indicating that the observed growth may be due to random chance rather than the effect of the fertilizer.

Considering this logic, the appropriate response would be:

The data and simulations show no evidence that the fertilizer encourages growth. The average height falls in the bin near the center of the distribution, between 0–2, indicating that the difference is not unusual.

This answer reflects the interpretation that if the average difference is not unusual according to the simulation, then the fertilizer effect cannot be conclusively claimed.