Question

5. What percentage of the offspring from a monohybrid cross of two heterozygous guinea pigs will be hairless?(1 point)
Responses

25%
25%

50%
50%

75%
75%

100%
100%

Answer 1

In a monohybrid cross of two heterozygous guinea pigs (genotype Aa × Aa), where "A" represents the allele for normal hair and "a" represents the allele for hairlessness (assuming hairlessness is recessive), you can use a Punnett square to determine the offspring ratios.

- Possible genotypes from the cross:
- AA (normal hair)
- Aa (normal hair)
- Aa (normal hair)
- aa (hairless)

From the Punnett square, the genotypic ratio is:
- 1 AA
- 2 Aa
- 1 aa

This means 1 out of 4 offspring will be hairless (aa).

To find the percentage of hairless offspring:
\[ \frac{1}{4} \times 100 = 25\% \]

Therefore, the percentage of the offspring that will be hairless is **25%**.