Question
A block initially at rest on a horizontal, frictionless surface is accelerated by a constant horizontal force of 5.0 newtons. If 15 joules of work is done on the block by this force while accelerating it, the kinetic energy of the block increases by
Answers
GPT-4o mini
According to the work-energy principle, the work done on an object is equal to the change in its kinetic energy. In this case, since the block is initially at rest, the increase in kinetic energy is equal to the work done on it by the force.
Given that 15 joules of work is done on the block, we can directly conclude that the increase in kinetic energy (\( \Delta KE \)) of the block is:
\[
\Delta KE = \text{Work done} = 15 \, \text{joules}
\]
Thus, the kinetic energy of the block increases by **15 joules**.
Given that 15 joules of work is done on the block, we can directly conclude that the increase in kinetic energy (\( \Delta KE \)) of the block is:
\[
\Delta KE = \text{Work done} = 15 \, \text{joules}
\]
Thus, the kinetic energy of the block increases by **15 joules**.