To solve the equation \( \ln(3) = \ln(12 - 12x) \), we can use the property of logarithms that states if \( \ln(a) = \ln(b) \), then \( a = b \). This leads us to the following equation:
\[ 3 = 12 - 12x \]
Next, we will solve for \( x \). Subtract 12 from both sides:
\[ 3 - 12 = -12x \]
This simplifies to:
\[ -9 = -12x \]
Now, divide both sides by -12:
\[ x = \frac{-9}{-12} = \frac{9}{12} = \frac{3}{4} \]
Thus, the correct solution is:
\[ x = \frac{3}{4} \]
So the correct response from the options provided is:
x equals Start Fraction 3 over 4 End Fraction