To demonstrate how the Product Rule of Logarithms works for the expression \( \log_4{16} + \log_4{4} \), we need to show that this sum is equal to the logarithm of the product of the two values. According to the Product Rule, we have:
\[ \log_b{A} + \log_b{B} = \log_b{(A \cdot B)} \]
In your example, we want to evaluate \( \log_4{16} + \log_4{4} \) and show that it equals \( \log_4{(16 \cdot 4)} \), which simplifies to \( \log_4{64} \).
So the option that best describes this process is:
Evaluate both \( \log_4{16} \) and \( \log_4{4} \) and show that their sum is equal to the value of \( \log_4{64} \).