Which of the following correctly changes log25200

to an equivalent expression?(1 point)
Responses

log200log525
Start Fraction logarithm 200 over logarithm subscript 5 baseline 25 End Fraction

log200log25
Start Fraction logarithm 200 over logarithm 25 End Fraction

log25log200
Start Fraction logarithm 25 over logarithm 200 End Fraction

log200ln25
Start Fraction logarithm 200 over l n 25 End Fraction

1 answer

To change \( \log_{25} 200 \) to an equivalent expression, we can use the change of base formula for logarithms, which is:

\[ \log_a b = \frac{\log_c b}{\log_c a} \]

where \( c \) can be any base, typically base 10 (common logarithm) or base \( e \) (natural logarithm).

If we choose \( c = 10 \), we can write:

\[ \log_{25} 200 = \frac{\log_{10} 200}{\log_{10} 25} \]

If we choose \( c = e \) (using natural logarithms), it becomes:

\[ \log_{25} 200 = \frac{\ln 200}{\ln 25} \]

Now, looking at your options, we can find the equivalent expression:

  1. \( \frac{\log 200}{\log 525} \)
  2. \( \frac{\log 200}{\log 25} \) - This matches what we found.
  3. \( \frac{\log 25}{\log 200} \)
  4. \( \frac{\log 200}{\ln 25} \)

The correct answer is:

\[ \frac{\log 200}{\log 25} \]

So, the equivalent expression for \( \log_{25} 200 \) is:

log200 / log25.