Asked by nati
What is the area of the quadrilateral?
(1 point)
Responses
460 cm2
460 cm squared
220 cm2
220 cm squared
480 cm2
480 cm squared
240 cm2
240 cm squared
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Given a trapezoid
24cm base
20cm top
10cm inside
(1 point)
Responses
460 cm2
460 cm squared
220 cm2
220 cm squared
480 cm2
480 cm squared
240 cm2
240 cm squared
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Given a trapezoid
24cm base
20cm top
10cm inside
Answers
Answered by
GPT-4o mini
To find the area of a trapezoid, we can use the formula:
\[
\text{Area} = \frac{1}{2} \times (b_1 + b_2) \times h
\]
where \( b_1 \) and \( b_2 \) are the lengths of the two bases and \( h \) is the height.
In your case:
- \( b_1 = 24 \) cm (the length of the bottom base)
- \( b_2 = 20 \) cm (the length of the top base)
- \( h = 10 \) cm (the height)
Now plugging in the values:
\[
\text{Area} = \frac{1}{2} \times (24 \text{ cm} + 20 \text{ cm}) \times 10 \text{ cm}
\]
\[
= \frac{1}{2} \times 44 \text{ cm} \times 10 \text{ cm}
\]
\[
= \frac{1}{2} \times 440 \text{ cm}^2
\]
\[
= 220 \text{ cm}^2
\]
So, the area of the trapezoid is **220 cm²**.
\[
\text{Area} = \frac{1}{2} \times (b_1 + b_2) \times h
\]
where \( b_1 \) and \( b_2 \) are the lengths of the two bases and \( h \) is the height.
In your case:
- \( b_1 = 24 \) cm (the length of the bottom base)
- \( b_2 = 20 \) cm (the length of the top base)
- \( h = 10 \) cm (the height)
Now plugging in the values:
\[
\text{Area} = \frac{1}{2} \times (24 \text{ cm} + 20 \text{ cm}) \times 10 \text{ cm}
\]
\[
= \frac{1}{2} \times 44 \text{ cm} \times 10 \text{ cm}
\]
\[
= \frac{1}{2} \times 440 \text{ cm}^2
\]
\[
= 220 \text{ cm}^2
\]
So, the area of the trapezoid is **220 cm²**.