To find the area of a trapezoid, we can use the formula:
\[ \text{Area} = \frac{1}{2} \times (b_1 + b_2) \times h \]
where \( b_1 \) and \( b_2 \) are the lengths of the two bases and \( h \) is the height.
In your case:
- \( b_1 = 24 \) cm (the length of the bottom base)
- \( b_2 = 20 \) cm (the length of the top base)
- \( h = 10 \) cm (the height)
Now plugging in the values:
\[ \text{Area} = \frac{1}{2} \times (24 \text{ cm} + 20 \text{ cm}) \times 10 \text{ cm} \]
\[ = \frac{1}{2} \times 44 \text{ cm} \times 10 \text{ cm} \]
\[ = \frac{1}{2} \times 440 \text{ cm}^2 \]
\[ = 220 \text{ cm}^2 \]
So, the area of the trapezoid is 220 cm².