To calculate the surface area of the cheese wheel, which is a cylinder, we use the formula for the surface area of a cylinder:
\[ \text{Surface Area} = 2\pi r(h + r) \]
Where:
- \( r \) is the radius of the base of the cylinder
- \( h \) is the height of the cylinder
- \( \pi \) is approximately 3.14
Given:
- The diameter of the cheese wheel is 6 inches, so the radius \( r \) is: \[ r = \frac{diameter}{2} = \frac{6}{2} = 3 \text{ inches} \]
- The height \( h \) is 2 inches.
Now, plug \( r \) and \( h \) into the surface area formula:
\[ \text{Surface Area} = 2 \times 3.14 \times 3 \times (2 + 3) \]
Calculating \( (h + r) \):
\[ h + r = 2 + 3 = 5 \]
Now substitute that back into the surface area formula:
\[ \text{Surface Area} = 2 \times 3.14 \times 3 \times 5 \]
Calculate:
\[ 2 \times 3.14 = 6.28 \] \[ 6.28 \times 3 = 18.84 \] \[ 18.84 \times 5 = 94.2 \]
Therefore, the total surface area of the cheese wheel is:
\[ \text{Surface Area} = 94.2 \text{ square inches} \]
The correct answer is 94.2 square inches.