Is (-2, 6) a solution to the system of these linear equations: I + 2y = 10 and

Question

3г + y = 0? Why? (1 point)
• No, because the graphs intersect at (-2, 6).
• Yes, because the graphs don't intersect at (-2, 6).
O Yes, because the graphs intersect at (-2, 6).
• No, because the graphs don't intersect at (-2, 6).

Answer 1

To determine if the point (-2, 6) is a solution to the system of equations \( I + 2y = 10 \) and \( 3g + y = 0 \), we will substitute \( x = -2 \) and \( y = 6 \) into both equations.

1. For the first equation \( I + 2y = 10 \):

   Substitute \( y = 6 \): \[ I + 2(6) = 10 \ I + 12 = 10 \ I = 10 - 12 \ I = -2 \]

2. For the second equation \( 3g + y = 0 \):

   Substitute \( g = -2 \) and \( y = 6 \): \[ 3(-2) + 6 = 0 \ -6 + 6 = 0 \ 0 = 0 \quad \text{(True)} \]

Since the point (-2, 6) satisfies both equations, it is indeed a solution to the system.

So, the answer would be: Yes, because the graphs intersect at (-2, 6).