Question
You have sampled a population in which you know that the percentage of the homozygous dominant genotype (AA) is 16%. Using that 16%, calculate the following - the frequency of the "A" allele. (p) p2 + 2pq + q2 = 1 and p + q = 1 a 1 b 0.4 c 0.16 d 0.36
Answers
GPT-4o mini
To find the frequency of the "A" allele (p), we can use the information provided about the homozygous dominant genotype (AA).
1. From the Hardy-Weinberg principle, we know that:
- \( p^2 + 2pq + q^2 = 1 \)
where \( p^2 \) represents the frequency of the AA genotype, \( 2pq \) represents the frequency of the heterozygous genotype (Aa), and \( q^2 \) represents the frequency of the homozygous recessive genotype (aa).
2. You have stated that the frequency of the AA genotype (homozygous dominant) is 16%, or 0.16. Therefore:
\[
p^2 = 0.16
\]
3. To find \( p \), take the square root of \( p^2 \):
\[
p = \sqrt{0.16} = 0.4
\]
Thus, the frequency of the "A" allele (p) is **0.4**.
Given the options:
- a) 1
- b) 0.4
- c) 0.16
- d) 0.36
The correct answer is **b) 0.4**.
1. From the Hardy-Weinberg principle, we know that:
- \( p^2 + 2pq + q^2 = 1 \)
where \( p^2 \) represents the frequency of the AA genotype, \( 2pq \) represents the frequency of the heterozygous genotype (Aa), and \( q^2 \) represents the frequency of the homozygous recessive genotype (aa).
2. You have stated that the frequency of the AA genotype (homozygous dominant) is 16%, or 0.16. Therefore:
\[
p^2 = 0.16
\]
3. To find \( p \), take the square root of \( p^2 \):
\[
p = \sqrt{0.16} = 0.4
\]
Thus, the frequency of the "A" allele (p) is **0.4**.
Given the options:
- a) 1
- b) 0.4
- c) 0.16
- d) 0.36
The correct answer is **b) 0.4**.