Question

Raphael wants to purchase an exercise ball. The dimensions state that the ball is 20 inches in diameter when at maximum capacity. How much air can the exercise ball hold when pumped to the maximum capacity? Calculate your answer using 3.14 for pi and round to the nearest tenth.(1 point)
inches3

1 answer

To find the volume of the exercise ball, we can use the formula for the volume of a sphere:

\[ V = \frac{4}{3} \pi r^3 \]

where \( r \) is the radius of the sphere.

  1. Calculate the radius: The diameter of the ball is 20 inches, so the radius \( r \) is half of that:

\[ r = \frac{20}{2} = 10 \text{ inches} \]

  1. Substitute the radius into the volume formula: \[ V = \frac{4}{3} \times 3.14 \times (10)^3 \]

  2. Calculate \( (10)^3 \): \[ (10)^3 = 1000 \]

  3. Now calculate the volume: \[ V = \frac{4}{3} \times 3.14 \times 1000 \]

  4. Calculate \( \frac{4}{3} \times 3.14 \): \[ \frac{4}{3} \times 3.14 \approx 4.18667 \]

  5. Now, multiply by 1000: \[ V \approx 4.18667 \times 1000 \approx 4186.67 \]

  6. Round to the nearest tenth: \[ V \approx 4186.7 \text{ inches}^3 \]

Therefore, the exercise ball can hold approximately 4186.7 inches³ of air when pumped to maximum capacity.