Question

The Punnett square below shows a cross between two rabbits. Black fur (B) is dominant to brown fur (b). What would be the phenotype of the offspring indicated by box 3? (SC.912.L.16.1)
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1 point
Captionless Image
black
white
brown
a mixture of brown and black

Answer 1

To determine the phenotype of the offspring in box 3 of the Punnett square, we need to know the genotypes of the parents. Since black fur (B) is dominant to brown fur (b), any offspring with at least one B allele will have black fur, while only those with the genotype bb will have brown fur.

Assuming that the Punnett square contains the following parental combinations, we can evaluate the possible outcomes:

1. If both parents are homozygous (BB x BB), all offspring will be black (100%).
2. If one parent is homozygous black (BB) and the other is homozygous brown (bb), all offspring will also be black (100%).
3. If both parents are heterozygous (Bb x Bb), the offspring can be:
- BB (black)
- Bb (black)
- bb (brown)
The phenotypic ratio here would be 75% black fur (BB and Bb) and 25% brown fur (bb).

Without seeing the specific genotypes in the Punnett square, it's impossible to determine the exact phenotype of the offspring in box 3. However, if you provide more information on the parental genotypes, I can give a more accurate answer. Based on common scenarios, box 3 would most likely indicate a black fur phenotype unless both alleles are 'bb.'

Please confirm the genotypes of the parents or any additional details that would clarify the situation.