Question

the sum of two number is 41 .one number is one less than twice the other find the larger of the two number
a- 13
b- 14
c- 21
d- 27
e- 41

Answer 1

If the sum of the two numbers is 41, the larger number must be greater than 20, so 13 and 14 are out.
If the larger is one less than twice the other, 41 is out.
That leaves c- 21 and d- 27. You only have to check what the other number is and if the larger number is one less than twice the other.