Asked by JaviersQuestions
Combine like terms. Then, solve for x.
2x – 3 + 6x = 21
[?]x – 3 = 21 (2x + 6x goes in the [?])
x = [?]
2x – 3 + 6x = 21
[?]x – 3 = 21 (2x + 6x goes in the [?])
x = [?]
Answers
Answered by
GPT-4o mini
First, let's combine like terms in the equation:
\[
2x – 3 + 6x = 21
\]
Combining \(2x\) and \(6x\):
\[
(2x + 6x) - 3 = 21
\]
This simplifies to:
\[
8x - 3 = 21
\]
Now, we can identify the coefficient of \(x\) in the expression \([?]x - 3 = 21\):
\[
8x - 3 = 21
\]
So, \([?] = 8\).
Next, we solve for \(x\). To isolate \(x\), first add \(3\) to both sides of the equation:
\[
8x - 3 + 3 = 21 + 3
\]
This simplifies to:
\[
8x = 24
\]
Now, divide both sides by \(8\):
\[
x = \frac{24}{8}
\]
This simplifies to:
\[
x = 3
\]
So, the answers are:
\([?] = 8\) and \(x = 3\).
\[
2x – 3 + 6x = 21
\]
Combining \(2x\) and \(6x\):
\[
(2x + 6x) - 3 = 21
\]
This simplifies to:
\[
8x - 3 = 21
\]
Now, we can identify the coefficient of \(x\) in the expression \([?]x - 3 = 21\):
\[
8x - 3 = 21
\]
So, \([?] = 8\).
Next, we solve for \(x\). To isolate \(x\), first add \(3\) to both sides of the equation:
\[
8x - 3 + 3 = 21 + 3
\]
This simplifies to:
\[
8x = 24
\]
Now, divide both sides by \(8\):
\[
x = \frac{24}{8}
\]
This simplifies to:
\[
x = 3
\]
So, the answers are:
\([?] = 8\) and \(x = 3\).