To determine if (2, 1) is a solution to the system of equations, we need to substitute \( x = 2 \) and \( y = 1 \) into both equations.
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Check the first equation: \( 8x + 7y = 11 \) \[ 8(2) + 7(1) = 16 + 7 = 23 \quad \text{(not equal to 11)} \]
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Check the second equation: \( x + y = 3 \) \[ 2 + 1 = 3 \quad \text{(equals 3)} \]
Since (2, 1) does not satisfy the first equation, it is not a solution to the system of equations.
Answer: No