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Solve the system of equations. 3x+y=2 7x−4y=30 (1 point) Responses (12, 12) left parenthesis start fraction 1 over 2 end fracti...Asked by botfor1
Solve the system of equations.
3x+y=2
7x−4y=30
(1 point)
Responses
(12, 12)
left parenthesis start fraction 1 over 2 end fraction comma start fraction 1 over 2 end fraction right parenthesis
(2, −4)
left parenthesis 2 comma negative 4 right parenthesis
(2, −2)
left parenthesis 2 comma negative 2 right parenthesis
(−2, 8)
3x+y=2
7x−4y=30
(1 point)
Responses
(12, 12)
left parenthesis start fraction 1 over 2 end fraction comma start fraction 1 over 2 end fraction right parenthesis
(2, −4)
left parenthesis 2 comma negative 4 right parenthesis
(2, −2)
left parenthesis 2 comma negative 2 right parenthesis
(−2, 8)
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve the system of equations:
1. \( 3x + y = 2 \) (Equation 1)
2. \( 7x - 4y = 30 \) (Equation 2)
We can use substitution or elimination. Let's use substitution by solving Equation 1 for \( y \):
From Equation 1:
\[
y = 2 - 3x
\]
Now substitute \( y \) into Equation 2:
\[
7x - 4(2 - 3x) = 30
\]
\[
7x - 8 + 12x = 30
\]
\[
19x - 8 = 30
\]
\[
19x = 38
\]
\[
x = 2
\]
Now substitute \( x = 2 \) back into Equation 1 to find \( y \):
\[
y = 2 - 3(2)
\]
\[
y = 2 - 6
\]
\[
y = -4
\]
So the solution to the system of equations is:
\[
(x, y) = (2, -4)
\]
Thus, the answer is:
\((2, -4)\)
1. \( 3x + y = 2 \) (Equation 1)
2. \( 7x - 4y = 30 \) (Equation 2)
We can use substitution or elimination. Let's use substitution by solving Equation 1 for \( y \):
From Equation 1:
\[
y = 2 - 3x
\]
Now substitute \( y \) into Equation 2:
\[
7x - 4(2 - 3x) = 30
\]
\[
7x - 8 + 12x = 30
\]
\[
19x - 8 = 30
\]
\[
19x = 38
\]
\[
x = 2
\]
Now substitute \( x = 2 \) back into Equation 1 to find \( y \):
\[
y = 2 - 3(2)
\]
\[
y = 2 - 6
\]
\[
y = -4
\]
So the solution to the system of equations is:
\[
(x, y) = (2, -4)
\]
Thus, the answer is:
\((2, -4)\)
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