Question
A circle is drawn on a coordinate plane with the center point at (-4,6) and a radius of 2. Derive the equation of the circle from the given information. Fill in the missing information in the following equation.
(x - 1.__)^2 + (y - 2.__)^2 = 3.__
1.
a. -4
b. -2
c. 4
d. 2
2.
a. 6
b. -6
c. 3
d. -3
3.
a. 4
b. -4
c. 1
d. -1
(x - 1.__)^2 + (y - 2.__)^2 = 3.__
1.
a. -4
b. -2
c. 4
d. 2
2.
a. 6
b. -6
c. 3
d. -3
3.
a. 4
b. -4
c. 1
d. -1
Answers
GPT-4o mini
The general form of the equation of a circle with center \((h, k)\) and radius \(r\) is given by:
\[
(x - h)^2 + (y - k)^2 = r^2
\]
From the information provided, the center of the circle is at \((-4, 6)\) and the radius is \(2\). Thus:
- \(h = -4\)
- \(k = 6\)
- \(r = 2\)
Now we can plug these values into the equation:
The radius squared is:
\[
r^2 = 2^2 = 4
\]
Therefore, the equation of the circle becomes:
\[
(x - (-4))^2 + (y - 6)^2 = 4
\]
This simplifies to:
\[
(x + 4)^2 + (y - 6)^2 = 4
\]
Now, we'll fill in the missing information in the provided equation format \((x - 1.__)^2 + (y - 2.__)^2 = 3.__\):
1. For \(x\), the value is \(+4\), which corresponds to \(-(-4)\). Hence, \(1.__ = 4\), and we select:
- a. **-4**
2. For \(y\), we have \(y - 6\), so \(2.__ = 6\), and we select:
- a. **6**
3. For the right side, we have \(4\) from \(r^2\), thus \(3.__ = 4\), and we select:
- a. **4**
So the answers are:
1. **a. -4**
2. **a. 6**
3. **a. 4**
\[
(x - h)^2 + (y - k)^2 = r^2
\]
From the information provided, the center of the circle is at \((-4, 6)\) and the radius is \(2\). Thus:
- \(h = -4\)
- \(k = 6\)
- \(r = 2\)
Now we can plug these values into the equation:
The radius squared is:
\[
r^2 = 2^2 = 4
\]
Therefore, the equation of the circle becomes:
\[
(x - (-4))^2 + (y - 6)^2 = 4
\]
This simplifies to:
\[
(x + 4)^2 + (y - 6)^2 = 4
\]
Now, we'll fill in the missing information in the provided equation format \((x - 1.__)^2 + (y - 2.__)^2 = 3.__\):
1. For \(x\), the value is \(+4\), which corresponds to \(-(-4)\). Hence, \(1.__ = 4\), and we select:
- a. **-4**
2. For \(y\), we have \(y - 6\), so \(2.__ = 6\), and we select:
- a. **6**
3. For the right side, we have \(4\) from \(r^2\), thus \(3.__ = 4\), and we select:
- a. **4**
So the answers are:
1. **a. -4**
2. **a. 6**
3. **a. 4**