Question 1

A)
Watch the videos to review the steps and see how problems were solved and explained. These problems are similar to those found on the test in this unit and will help you understand what is being asked and how to solve them correctly.

1. Intersecting Chords Theorem (Lesson 2)

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Using the picture below, set up a proportion and solve for d if a = 7 b = 4, and c =2


(1 point)
Responses

d = 21
d = 21

d = 14
d = 14

d = 25.9
d = 25.9

d = 8
d = 8
B)
2. Intersecting Secants Theorem (Lesson 2)

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Circle M has secant lines QR and UT that intersect at point S outside the circle. Find x if the measure of secant segment QS = 15, the measure of RS = 8, the measure of ST = 3x-2 and the measure of SU = 12

Four closed points on a circle are marked and labeled, as is a closed point outside of the circle and one at the center. Two lines, with arrows at both ends, cut through the edge of the circle at 4 closed points and intersect outside of it.







(1 point)
Responses

x = 10
x = 10

x = 4
x = 4

x = 120
x = 120

x= 12
x= 12
C)
3. Using the Pythagorean Theorem to solve the relationship between tangent lines and Radii when a right triangle is created. (Lesson 2)

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In the picture below, Line NM is tangent to circle O. What is the length in centimeters of NO rounded to the nearest tenth?

(1 point)
Responses

x= 7.3
x= 7.3

x= 7.2
x= 7.2

x= 6.8
x= 6.8

x= 53
x= 53
D)
4. Finding arc lengths using central angles measured in radians with a constant of proportionality. (Lesson 8)

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If a circle has a central angle of π3
and a radius of 5 mm. How long is the arc formed by that angle?

A circle with an angle that opens to the right. The center of the circle is identified by a closed point from which the angle lines extend.



(1 point)
Responses

25π3
25pi over 3

35π
3 over 5 pi

15π
15pi

5π3
5 pi over 3
E)
5. Finding scale factors of similar circles. (Lesson 6)

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If circle O is constructed so that it has a circumference of 160 meters and is dilated to create circle O' with a circumference of 400 meters, then what is the scale factor? Enter any non-whole number as a fraction.



(1 point)
Responses

52
5 halves

25
2 fifths

2.5
2.5

6
6
F)
6. Finding the area of a sector (Lesson 9)

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What is the area of the sector of a circle with θ
= 196°
and a radius of 6 inches? Express your answer in terms of π



(1 point)
Responses

19.6π
in2
19.6piin2

5.4π
in2
5.4piin2

1176π
in2
1176piin2

32.7π
in2
32.7piin2
G)
7. Finding the area of a sector (Lesson 9)

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Dave ordered a large Domino's pizza. The large pizzas have a diameter of 15 inches. The delivery driver ended up eating part of the pizza on the way to Dave's house. The missing section forms an angle of 220 degrees. What is the area of the pizza that was eaten? Round your answer to the nearest tenth.



(1 point)
Responses

108.0 square inches
108.0 square inches

46.1 square inches
46.1 square inches

89.4 square inches
89.4 square inches

14.7 square inches
14.7 square inches
H)
8. Explaining arc length with radians. (Lesson 8)

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The formula for the circumference of a circle is C = πd
where C = circumference and d
= diameter. It can also be defined as C = 2πr
where r
=radius. If 360 degrees = 2π
radians, and the proportional relationship θ
= sr
, is given and s
= arc length, then determine the length created by a 60 degree central angle in a circle with a 10 inch diameter and explain how you found it. Leave your answer in terms of pi. You may type out your work or upload it.



Which of the following would be the best way to answer this question for full credit?

(1 point)
Responses

The answer is 5π3
because we plugged in the known angle of 60 degrees in terms of radians by taking 60360
or simplified to 16
of 2π
to get π3
as the central angle in terms of radians. Next, we use the known proportional relationship replacing the angle and radius of 5 as it is half of the diameter given to get π3=s5
. By multiplying both sides by 5 we solve for our arc length and get 5π3=s
The answer is 5 pi over 3 because we plugged in the known angle of 60 degrees in terms of radians by taking 60 over 360 or simplified to 1 sixth of 2pi to get pi over 3 as the central angle in terms of radians. Next, we use the known proportional relationship replacing the angle and radius of 5 as it is half of the diameter given to get pi over 3 is equal to s over 5. By multiplying both sides by 5 we solve for our arc length and get 5 pi over 3 is equal to s

The answer is 5.24
The answer is 5.24

I don't know
I don't know

I'd leave this question blank even though it is worth 3 points and will hurt my overall grade by a lot for not attempting it.
I'd leave this question blank even though it is worth 3 points and will hurt my overall grade by a lot for not attempting it.
I)
9. Using the Inscribed Quadrilateral Theorem to solve problems. (Lesson 5)

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Quadrilateral PQRS is inscribed inside circle O. The opposite angles are P and R. Angle P measures (x+28) degrees and angle R measures (3x-12) degrees respectively. Determine the measure of angle R. Show all work in order to receive full credit. You may upload a picture of your work using the picture button or type your answer in.

(1 point)
Responses

111 degrees
111 degrees

x = 41
x = 41

x = 20
x = 20

48 degrees
48 degrees
J)
10. Finding lengths of segments inside a circle. (Lesson 2)

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KM and KL are tangent to the circle. Angle MFK = 31°
and LK = 24 ft. How long is MF to the nearest foot?

A circle has center point upper F. The circumference point upper L is at the left of the circle and the circumference point upper M is at the right of the circle. Point upper K is above the circle in line with upper F.

(1 point)
Responses

26 ft
26 ft

40 ft
40 ft

29 ft

1 answer

Here are the answers for each of the problems you provided based on the provided scenarios and mathematics involved:

A) Intersecting Chords Theorem

To find \(d\) using the intersecting chords theorem, we can set up the proportion: \[ a \cdot b = c \cdot d \] Substituting the values: \[ 7 \cdot 4 = 2 \cdot d \] This simplifies to: \[ 28 = 2d \implies d = 14 \] Answer: d = 14


B) Intersecting Secants Theorem

Using the formula for intersecting secants: \[ QS \cdot RS = ST \cdot SU \] Plugging in the values: \[ 15 \cdot 8 = (3x - 2) \cdot 12 \implies 120 = (3x - 2) \cdot 12 \] Divide both sides by 12: \[ 10 = 3x - 2 \implies 3x = 12 \implies x = 4 \] Answer: x = 4


C) Pythagorean Theorem for Tangents and Radii

Using the Pythagorean theorem in the right triangle formed by the radius and the tangent: \[ NO^2 + OA^2 = NA^2 \] Since the radius \(OA\) is not provided, we can't calculate a specific length for \(NO\). However, if we assume, for example, that \(OA\) is a known distance (like 5 cm), you plug in that value to compute \(NO\). Assuming the derived values are options to choose from: Let's say \(NA = 7\)cm, then using: \[ NO^2 + 5^2 = 7^2 \implies NO^2 + 25 = 49 \implies NO^2 = 24 \implies NO = \sqrt{24} \approx 4.9 \]

Without specific parameters, evaluate each option. Answer: Unclear without additional information.


D) Arc Length with Radians

The formula for arc length \(s\) is: \[ s = r\theta \] Where \(r = 5\) mm and \(\theta = \frac{\pi}{3}\): \[ s = 5 \cdot \frac{\pi}{3} = \frac{5\pi}{3} \] Answer: 5π/3


E) Scale Factor of Similar Circles

The scale factor is the ratio of the circumferences: \[ \text{Scale factor} = \frac{400}{160} = \frac{5}{2} \] Answer: 2.5


F) Area of a Sector

To find the area of a sector: \[ \text{Area} = \frac{\theta}{360} \cdot \pi r^2 \] With \(\theta = 196^\circ\) and \(r = 6\): \[ \text{Area} = \frac{196}{360} \cdot \pi \cdot 6^2 = \frac{196}{360} \cdot \pi \cdot 36 \] Calculating gives approximately: \[ \text{Area} = \frac{196 \cdot 36}{360} \pi \approx 19.6\pi \] Answer: 19.6π in²


G) Area of Eaten Pizza

Using the same area of sector formula with the pizza diameter \(d = 15\) inches, so \(r = 7.5\): \[ \text{Area} = \frac{220}{360} \cdot \pi \cdot (7.5)^2 = \frac{220}{360} \cdot \pi \cdot 56.25 \approx 108.0 \text{ square inches} \] Answer: 108.0 square inches


H) Arc Length with Radians

For the 60-degree angle, convert it to radians: \[ \frac{60}{360} = \frac{1}{6} \Rightarrow \theta = \frac{\pi}{3} \] Calculating arc length as: \[ s = r\theta = 5 \cdot \frac{\pi}{3} = \frac{5\pi}{3} \] Answer: 5π/3


I) Inscribed Quadrilateral Theorem

Setting the angles equal (since angles P and R add up to 180 degrees): \[ (x + 28) + (3x - 12) = 180 \] Solving: \[ 4x + 16 = 180 \implies 4x = 164 \implies x = 41 \] Now calculating angle \(R\): \[ R = 3(41) - 12 = 123 \] Answer: x = 41


J) Segment Length Inside a Circle

Since \(KM\) and \(KL\) are tangent to the circle: Using trigonometry, we have: \[ MF = KL \cdot \sin(31^\circ) \] Without specific hypotenuse information or options, please evaluate the answers through the tangential relationships or fed options. Answer: Unclear without additional information.


Feel free to clarify if you need more specific calculations or adjustments!