Question
Write the condensed electron configuration and partial orbital diagram for Se2-
Answers
GPT-4o mini
The element selenium (Se) has an atomic number of 34, meaning a neutral selenium atom has 34 electrons. The electron configuration for neutral selenium is:
\[ \text{[Ar]} \, 3d^{10} \, 4s^2 \, 4p^4 \]
When selenium gains two additional electrons to form the Se²⁻ ion, it will have a total of 36 electrons. The additional electrons are added to the highest energy orbitals, which in this case are the 4p orbitals. Therefore, the electron configuration for Se²⁻ can be written as:
\[ \text{[Ar]} \, 3d^{10} \, 4s^2 \, 4p^6 \]
This configuration indicates that the 4p subshell is now fully filled with 6 electrons.
### Partial Orbital Diagram
The partial orbital diagram for Se²⁻ can be represented as follows:
```
4p: ↑↓ ↑↓ ↑↓ (4 electrons in 4p, fully filled)
4s: ↑↓ (2 electrons in 4s, fully filled)
3d: ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ (10 electrons in 3d, fully filled)
```
In summary, for Se²⁻:
- The condensed electron configuration is \(\text{[Ar]} \, 3d^{10} \, 4s^2 \, 4p^6\).
- The orbital diagram shows fully filled s, p, and d orbitals.
\[ \text{[Ar]} \, 3d^{10} \, 4s^2 \, 4p^4 \]
When selenium gains two additional electrons to form the Se²⁻ ion, it will have a total of 36 electrons. The additional electrons are added to the highest energy orbitals, which in this case are the 4p orbitals. Therefore, the electron configuration for Se²⁻ can be written as:
\[ \text{[Ar]} \, 3d^{10} \, 4s^2 \, 4p^6 \]
This configuration indicates that the 4p subshell is now fully filled with 6 electrons.
### Partial Orbital Diagram
The partial orbital diagram for Se²⁻ can be represented as follows:
```
4p: ↑↓ ↑↓ ↑↓ (4 electrons in 4p, fully filled)
4s: ↑↓ (2 electrons in 4s, fully filled)
3d: ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ (10 electrons in 3d, fully filled)
```
In summary, for Se²⁻:
- The condensed electron configuration is \(\text{[Ar]} \, 3d^{10} \, 4s^2 \, 4p^6\).
- The orbital diagram shows fully filled s, p, and d orbitals.