If \( y = 12x + 7 \) is changed to \( y = 12x + 2 \), the graph of the new function would be a vertical shift downward. Specifically, it would move down by 5 units because the constant term changed from 7 to 2. Therefore, every point on the original graph would be 5 units lower on the new graph. The slope (12) remains the same, so the steepness of the line does not change; only the y-intercept changes.
Fill in the Blank
1 point
Question at position 25
If y = 12x + 7 were changed to y = 12x + 2, how would the graph of the new function compare with the original?
1 answer